15x^-1/3x^-3=0

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Solution for 15x^-1/3x^-3=0 equation:



15x^-1/3x^-3=0
Domain of the equation: 3x^!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
15x-1/3x^-3=0
We multiply all the terms by the denominator
15x*3x^-3*3x^-1=0
Wy multiply elements
45x^2-9x-1=0
a = 45; b = -9; c = -1;
Δ = b2-4ac
Δ = -92-4·45·(-1)
Δ = 261
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{261}=\sqrt{9*29}=\sqrt{9}*\sqrt{29}=3\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{29}}{2*45}=\frac{9-3\sqrt{29}}{90} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{29}}{2*45}=\frac{9+3\sqrt{29}}{90} $

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